A) \[\pi A/2\]
B) \[\pi A\]
C) \[2\pi A\]
D) \[A\]
Correct Answer: C
Solution :
Wave velocity\[v=\frac{\lambda }{T}=\frac{\omega \lambda }{2\pi }\] Maximum particle velocity \[{{({{v}_{\max }})}_{\rho }}=A\omega \] Given, \[v={{({{v}_{\max }})}_{\rho }}\] \[\frac{\omega \lambda }{2\pi }=A\omega \] \[\Rightarrow \] \[\lambda =2\pi A\]
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