A) \[-\frac{3GM}{a}\]
B) \[-\frac{2GM}{a}\]
C) \[-\frac{GM}{a}\]
D) \[-\frac{4GM}{a}\]
Correct Answer: A
Solution :
Gravitational potential at point a/ 2 distance from centre\[=-\frac{GM}{a}-\frac{GM}{a/2}\] \[=-\frac{3GM}{a}\]You need to login to perform this action.
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