A) 1s
B) 2s
C) 3s
D) 4s
Correct Answer: B
Solution :
Time period in vibration magnetometer \[T=2\pi \sqrt{\frac{I}{M\times {{B}_{H}}}}\] \[\Rightarrow \] \[T\propto \frac{1}{\sqrt{B{{ & }_{H}}}}\] \[\Rightarrow \] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{({{B}_{H}})}_{2}}}{{{({{B}_{H}})}_{1}}}}\] \[\Rightarrow \] \[\frac{2}{{{T}_{2}}}=\sqrt{\frac{18}{24}}\] \[T=2.3s\approx 2s\]You need to login to perform this action.
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