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NEET AIPMT SOLVED PAPER SCREENING 2010

  • question_answer
    A conducting circular loop is placed in a uniform magnetic field, B = 0.025 T with its plane perpendicular to the loop. The radius of the loop is made to shrink at a constant rate of \[\text{1}\,\text{m}{{\text{m}}^{\text{s-1}}}\]. The induced emf when the radius is 2 cm, is

    A) \[\text{2}\,\text{V}\]

    B)                        \[\,\text{V}\]

    C) \[\frac{\pi }{2}\,\text{V}\]          

    D)        \[\text{2}\,\text{V}\]

    Correct Answer: B

    Solution :

    Magnetic flux \[\phi =B\cdot A\] \[=B\cdot \pi {{r}^{2}}\] Induced emf,\[|e|=\frac{d\phi }{dt}=B\pi 2r\frac{dr}{dt}\] \[=0.025\times \pi \times 2\times 2\times {{10}^{-2}}\times 1\times {{10}^{-3}}\] \[=\pi \,\mu \,V\]


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