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NEET AIPMT SOLVED PAPER SCREENING 2010

  • question_answer
    The mass of a \[_{\text{3}}^{\text{7}}\] Li nucleus is 0.042u less than the sum of the masses of all its nucleons. The binding energy per nucleon of \[_{\text{3}}^{\text{7}}\]Li nucleus is nearly

    A)                                         46 MeV                               

    B) 5.6 MeV                              

    C) 3.9 MeV              

    D)        23 MeV

    Correct Answer: B

    Solution :

    If \[m=1u,c=3\times {{10}^{8}}m{{s}^{-1}},\]then \[E=931\,\,MeV\,ie,\,\,1\,u=931\,\,MeV\] Binding energy \[=0.042\,\times 931=39.10\,\,\text{MeV}\] \[\therefore \]Binding energy per nucleon                                 \[=\frac{39.10}{7}=5.58\approx 5.6MeV\]


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