A) \[\frac{1}{2}\frac{I_{b}^{2}}{({{I}_{t}}+{{I}_{b}})}\omega _{i}^{2}\]
B) \[\frac{1}{2}\frac{I_{t}^{2}}{({{I}_{t}}+{{I}_{b}})}\omega _{i}^{2}\]
C) \[\frac{1}{2}\frac{{{I}_{b}}-{{I}_{t}}}{({{I}_{t}}+{{I}_{b}})}\omega _{i}^{2}\]
D) \[\frac{1}{2}\frac{{{I}_{b}}{{I}_{t}}}{({{I}_{t}}+{{I}_{b}})}\omega _{i}^{2}\]
Correct Answer: D
Solution :
Loss of energy,\[\Delta E=\frac{1}{2}{{I}_{t}}\omega _{i}^{2}-\frac{1}{2}\frac{I_{t}^{2}\omega _{i}^{2}}{2({{I}_{t}}+{{I}_{b}})}\] \[=\frac{1}{2}\frac{I_{b}^{{}}{{I}_{t}}\omega _{i}^{2}}{({{I}_{t}}+{{I}_{b}})}\]You need to login to perform this action.
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