A) 3v/4
B) 6v
C) 12 v
D) 3v/2
Correct Answer: B
Solution :
Orbital velocity of satellite \[v=\sqrt{\frac{GM}{r}}\] \[\Rightarrow \] \[\frac{{{v}_{A}}}{{{v}_{B}}}=\sqrt{\frac{{{r}_{B}}}{{{r}_{A}}}}=\sqrt{\frac{R}{4R}}=\frac{1}{2}\] \[\therefore \] \[\frac{{{v}_{A}}}{{{v}_{B}}}=\frac{3v}{{{v}_{B}}}=\frac{1}{2}\] \[\therefore \] \[{{v}_{B}}=6v\]You need to login to perform this action.
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