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NEET AIPMT SOLVED PAPER SCREENING 2010

  • question_answer
    The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200nm falls on it, must be

    A) 2.4 V

    B)                        -1.2 V

    C) 2.4 V     

    D)        1.2 V

    Correct Answer: D

    Solution :

    Energy      of      incident      light \[E(eV)=\frac{12375}{2000}=6.2eV(200nm=2000{\AA})\] According to the relation \[E={{W}_{0}}+e{{V}_{0}}\] \[\Rightarrow \]                               \[{{V}_{0}}=\frac{E-{{W}_{0}}}{e}\]                                 \[=\frac{(6.2-5.01)e}{e}\]                                 \[=1.2\,V\]


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