A) \[8\times {{10}^{4}}\,cal/K\]
B) \[80\,\,cal/K\]
C) \[293\,\,cal/K\]
D) \[273\,\,cal/K\]
Correct Answer: C
Solution :
Change in entropy \[\Delta S=\frac{ml}{T}=\frac{1000\times 80}{273}=293\,\text{cal}\,{{\text{K}}^{\text{-1}}}\]
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