A) is zero
B) depends upon the choice of the two materials of the thermocouple
C) is negative
D) is positive
Correct Answer: A
Solution :
We have \[e=at+b{{t}^{2}}\] \[\frac{de}{dt}=a+2bt\] Natural temperature \[{{T}_{n}}=-\frac{a}{2b}\] At netural temperature\[\frac{de}{dt}=0\]
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