A) \[{{h}^{2}}{{v}^{2}}/2M{{c}^{2}}\]
B) zero
C) \[hv\]
D) \[M{{c}^{2}}-hv\]
Correct Answer: A
Solution :
Momentum of a photon \[p=\frac{hv}{c}\] Hence, Recoil energy \[E=\frac{{{p}^{2}}}{2M}\] \[\therefore \] \[E=\frac{{{\left( \frac{hv}{c} \right)}^{2}}}{2M}\] or \[E=\frac{{{h}^{2}}{{v}^{2}}}{2M{{c}^{2}}}\]
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