A) 100 mA
B) 200 mA
C) 20 mA
D) 10 mA
Correct Answer: C
Solution :
Given,\[e=200\sqrt{2}\sin 100t\] and \[C=1\mu F\] \[{{E}_{rms}}=200\,\text{V}\] \[{{X}_{C}}=\frac{1}{\omega C}=\frac{1}{1\times {{10}^{-6}}\times 100}={{10}^{4}}\Omega \] \[{{i}_{rms}}=\frac{{{E}_{rms}}}{{{X}_{C}}}\] \[{{i}_{rms}}=\frac{200}{{{10}^{4}}}=2\times {{10}^{-2}}A=20mA\]
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