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NEET AIPMT SOLVED PAPER SCREENING 2011

  • question_answer
    An AC voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to \[3\,\Omega ,\]the phase difference between the applied voltage and the current in the circuit is

    A)  \[\pi /4\]                            

    B)  \[\pi /2\]                            

    C)  zero                                     

    D)  \[\pi /6\]

    Correct Answer: A

    Solution :

    \[\tan \phi =\frac{{{X}_{L}}}{R}=\frac{L\omega }{R}\] \[\tan \phi =\frac{3\,\Omega }{3\,\Omega }\] \[\tan \phi =1\]      \[\phi ={{\tan }^{-1}}(1)\]      \[\phi ={{45}^{o}}\]      \[\phi =\frac{\pi }{4}rad\]


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