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NEET AIPMT SOLVED PAPER SCREENING 2011

  • question_answer
    Force F on a particle moving in a straight line varies with distance d as shown in the figure. The work done on the particle during its displacement of 12 m is

    A)  21 J

    B)                                         26 J                       

    C)         13 J                       

    D)         18 J

    Correct Answer: C

    Solution :

    Work done = Area under (F - x) graph \[=2\times (7-3)+\frac{1}{2}\,\times 2\times (12-7)\] \[=8+\frac{1}{2}\times 10\] \[=8+5=13\,J\]


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