A) \[\tau =0.5\,s\]
B) \[\tau =0.25\,s\]
C) \[\tau =2\,s\]
D) \[\tau =1\,s\]
Correct Answer: D
Solution :
According to question, torque, \[\tau =0\] Its means that, \[\alpha =0\] \[\alpha =\frac{{{d}^{2}}\theta }{d{{t}^{2}}}\] Given \[\theta (t)=2{{t}^{3}}-6{{t}^{2}}\] So, \[\frac{d\theta }{dt}=6{{t}^{2}}-12t\] \[\frac{{{d}^{2}}\theta }{d{{t}^{2}}}=12t-12\left( \because \alpha =\frac{{{d}^{2}}\theta }{d{{t}^{2}}}=0 \right)\] \[12t-12=0\] \[t=1\,s\]You need to login to perform this action.
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