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NEET AIPMT SOLVED PAPER SCREENING 2011

  • question_answer
    Which of the two ions from the list given below, have the geometry that is explained by the same hybridisation          of          orbitals, \[NO_{2}^{-},NO_{3}^{-},NH_{2}^{-},NH_{4}^{+},SC{{N}^{-}}?\]

    A) \[NH_{4}^{-}\,and\,NO_{3}^{-}\]            

    B) \[SCN_{{}}^{-}\,and\,NH_{2}^{-}\]

    C)        \[NO_{2}^{-}\,and\,NH_{2}^{-}\]

    D)        \[NO_{2}^{-}\,and\,NH_{3}^{-}\]

    Correct Answer: D

    Solution :

    \[NO_{2}^{-}\xrightarrow[{}]{{}}s{{p}^{2}}\] \[NO_{3}^{-}\xrightarrow[{}]{{}}s{{p}^{2}}\] \[NO_{2}^{-}\xrightarrow[{}]{{}}s{{p}^{2}}\] \[NO_{4}^{-}\xrightarrow[{}]{{}}s{{p}^{3}}\] \[SC{{N}^{+}}\xrightarrow[{}]{{}}sp\] \[\therefore \]\[NO_{2}^{-}\]and \[NO_{3}^{-}\]both have the same hybridization.


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