A) \[\text{1}\text{.0J}\,\text{mo}{{\text{l}}^{\text{-1}}}\,{{\text{K}}^{\text{-1}}}\]
B) \[\text{0}\text{.1}\,\text{J}\,\text{mo}{{\text{l}}^{\text{-1}}}\,{{\text{K}}^{\text{-1}}}\]
C) \[100\,\text{J}\,\text{mo}{{\text{l}}^{\text{-1}}}\,{{\text{K}}^{\text{-1}}}\]
D) \[10\,\text{J}\,\text{mo}{{\text{l}}^{\text{-1}}}\,{{\text{K}}^{\text{-1}}}\]
Correct Answer: C
Solution :
\[\Delta {{G}^{o}}=\Delta {{H}^{o}}-T\Delta {{S}^{o}}\] Given, \[\Delta {{H}_{vap.}}=30\,kJ\,mo{{l}^{-1}}\] \[\Delta {{G}^{o}}=0\]at equilibrium, \[\Delta {{S}_{vap}}=\frac{\Delta {{H}_{vap}}}{T}\] \[=\frac{30\times {{10}^{3}}\,J\,mo{{l}^{-1}}}{300\,K}\] \[=100\,\,J\,mo{{l}^{-1}}\,{{K}^{-1}}\]
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