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NEET AIPMT SOLVED PAPER SCREENING 2011

  • question_answer
    A parallel plate condenser has a uniform electric field E (V/m) in the space between the plates. If the distance between the plates is d(m) and area of each plate is \[A({{m}^{2}})\] the energy (joule) stored in the condenser is

    A) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}\]

    B)                        \[{{\varepsilon }_{0}}EAd\]

    C) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}Ad\]     

    D)        \[{{E}^{2}}Ad/{{\varepsilon }_{0}}\]

    Correct Answer: C

    Solution :

    The energy stored in the condenser \[U=\frac{1}{2}C{{V}^{2}}\] \[U=\frac{1}{2}\left( \frac{A{{\varepsilon }_{0}}}{d} \right){{(Ed)}^{2}}\left( \because C=\frac{A{{\varepsilon }_{0}}}{d}\text{and}\,V=Ed \right)\] \[U=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}Ad\]


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