A) 12.25 u
B) 6.50 u
C) 25.00 u
D) 50.00 u
Correct Answer: A
Solution :
\[\frac{{{r}_{A}}}{{{r}_{B}}}=\sqrt{\frac{{{M}_{B}}}{{{M}_{A}}}}\] or \[\frac{{{V}_{A}}}{{{t}_{B}}}\times \frac{{{t}_{B}}}{{{V}_{B}}}=\sqrt{\frac{{{M}_{B}}}{{{M}_{A}}}}\] or\[\frac{10}{20}=\sqrt{\frac{{{M}_{B}}}{49}}\] or\[\frac{1}{4}=\frac{{{M}_{B}}}{49}\] \[\therefore \]\[{{M}_{B}}=\frac{49}{4}=12.25\,u.\]
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