A) 2.8
B) 4.0
C) 1.4
D) 2.0
Correct Answer: C
Solution :
Average velocity \[=\sqrt{\frac{8RT}{\pi M}}\] \[\therefore {{V}_{av}}\propto \sqrt{T}\]or\[\frac{{{({{V}_{av}})}_{2}}}{{{({{V}_{av}})}_{2}}}=\sqrt{\frac{2T}{T}}=1.4\]
You need to login to perform this action.
You will be redirected in
3 sec
