A) 75
B) 100
C) 25
D) 50
Correct Answer: D
Solution :
\[\beta =\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}}=\frac{(20-10)mA}{(300-100)mA}=\frac{10\times {{10}^{-3}}}{300\times {{100}^{-6}}}=50\]You need to login to perform this action.
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