A) \[{{\lambda }_{1}}=2{{\lambda }_{2}}\]
B) \[{{\lambda }_{1}}=4{{\lambda }_{2}}\]
C) \[{{\lambda }_{1}}=\frac{1}{2}{{\lambda }_{2}}\]
D) \[{{\lambda }_{1}}={{\lambda }_{2}}\]
Correct Answer: A
Solution :
\[{{E}_{1}}=25\,eV,{{E}_{2}}=50\,eV\]\[{{E}_{1}}=\frac{hc}{{{\lambda }_{1}}}\text{and}\,{{E}_{2}}=\frac{hc}{{{\lambda }_{2}}}\] or\[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\]or\[\frac{25}{50}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\]or\[{{\lambda }_{1}}=2{{\lambda }_{2}}\]
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