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NEET AIPMT SOLVED PAPER SCREENING 2011

  • question_answer
    Acidified \[{{\text{K}}_{\text{2}}}\text{C}{{\text{r}}_{\text{2}}}{{\text{O}}_{\text{7}}}\] solution turns green when \[\text{N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{3}}}\]is added to it. This is due to the formation of

    A) \[\text{CrO}_{4}^{2-}\]                

    B) \[\text{C}{{\text{r}}_{\text{2}}}{{\text{(S}{{\text{O}}_{\text{3}}}\text{)}}_{\text{3}}}\]

    C)        \[\text{CrS}{{\text{O}}_{4}}\]   

    D)        \[\text{C}{{\text{r}}_{\text{2}}}{{\text{(S}{{\text{O}}_{4}})}_{3}}\]

    Correct Answer: D

    Solution :

    \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+3N{{a}_{2}}S{{O}_{3}}+4{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}3N{{a}_{2}}S{{O}_{4}}\] \[+{{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{(S{{O}_{4}})}_{3}}+4{{H}_{2}}O\]


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