A) \[ns\xrightarrow[{}]{{}}(n-1)d\xrightarrow[{}]{{}}(n-2)f\xrightarrow[{}]{{}}np\]
B) \[ns-(n-2)f\xrightarrow[{}]{{}}np\xrightarrow[{}]{{}}(n-1)d\]
C) \[ns-np\xrightarrow[{}]{{}}(n-1)d\xrightarrow[{}]{{}}(n-2)f\]
D) \[ns\xrightarrow[{}]{{}}(n-2)f\xrightarrow[{}]{{}}(n-1)d\xrightarrow[{}]{{}}np\]
Correct Answer: D
Solution :
\[6s\to 4f\to 5d\to 6p\]for n = 6
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