A) Benedict test
B) Iodofrom test
C) Tollen's reagent test
D) Fehling solution test
Correct Answer: B
Solution :
\[C{{H}_{3}}CHO\] and \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}CHO\]both being aliphatic aldehydes react with Tollen's reagent, Fehling solution and Benedict solution. So, these reagents cannot be used to distinguish them. \[C{{H}_{3}}CHO\] reacts with NaOH and 12 to give yellow crystals' of iodoform while \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}CHO\] does not react with it. \[C{{H}_{3}}CHO+3{{I}_{2}}+4NaOH\xrightarrow[{}]{{}}CH{{I}_{3}}\] \[+HCOONa+3NaI+3{{H}_{2}}O\] \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}CHO+{{I}_{2}}+NaOH\xrightarrow[{}]{{}}No\]reaction Thus,\[C{{H}_{3}}CHO\]and\[{{C}_{6}}{{H}_{5}}C{{H}_{2}}CHO\]can be distinguished by iodoform test.You need to login to perform this action.
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