A) \[{{\text{H}}_{\text{2}}}\text{O}\]
B) \[\text{B}{{\text{F}}_{3}}\]
C) \[\text{NH}_{2}^{-}\]
D) \[\text{PC}{{\text{l}}_{\text{3}}}\]
Correct Answer: D
Solution :
\[{{H}_{2}}O\Rightarrow \] [bp = bond pairs and Ip = lone pair] Thus, in \[PC{{l}_{3}}\], the central atom P has three bond pairs and one lone pair.You need to login to perform this action.
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