A) \[\theta ={{\tan }^{-1}}\left( \frac{1}{4} \right)\]
B) \[\theta ={{\tan }^{-1}}(4)\]
C) \[\theta ={{\tan }^{-1}}(2)\]
D) \[\theta ={{45}^{o}}\]
Correct Answer: B
Solution :
Given, \[R=H\] Range \[R=\frac{{{u}^{2}}(2\sin \theta \cos \theta )}{g}\] Height \[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] Hence,\[\frac{{{u}^{2}}(2\sin \theta \cos \theta )}{g}=\frac{{{u}^{2}}{{\sin }^{2}}a}{2g}\] \[2\cos \theta =\frac{\sin \theta }{2}\] \[\tan \theta =4\] \[\theta ={{\tan }^{-1}}(4)\]
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