A) 5R
B) 15R
C) 3R
D) 4R
Correct Answer: C
Solution :
According to question\[\frac{GMm}{{{(R+h)}^{2}}}=\frac{1}{16}\frac{GMm}{{{R}^{2}}}\] \[\frac{1}{{{(R+h)}^{2}}}=\frac{1}{16{{R}^{2}}}\]or\[\frac{1}{R+h}=\frac{1}{4}\] or\[\frac{R+h}{R}=4\] \[h=3R\]
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