A) \[Q=-q\]
B) \[Q=-\frac{1}{q}\]
C) \[Q=q\]
D) \[Q=\frac{1}{q}\]
Correct Answer: A
Solution :
If potential at centre is zero, then \[{{V}_{1}}+{{V}_{2}}+{{V}_{3}}+{{V}_{4}}=0\] \[-\frac{kQ}{r}-\frac{kq}{r}+\frac{k2Q}{r}+\frac{k2q}{r}=0\] \[-Q-q+2q+2Q=0\] \[Q=-q\]You need to login to perform this action.
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