A) 2.4
B) 1.2
C) 4.8
D) 3.6
Correct Answer: C
Solution :
Nuclear radius \[r\propto {{A}^{1/3}},\], where A is mass number \[r={{r}_{0}}{{A}^{1/3}}\] \[r={{r}_{0}}{{(27)}^{1/3}}=3{{r}_{0}}\] \[{{r}_{0}}\frac{3.6}{3}=1.2\,\text{fm}\] For \[^{\text{64}}\text{Cu}\] \[r={{r}_{0}}{{A}^{1/3}}\] \[=1.2\,\text{fm}\,{{(64)}^{1/3}}\] \[=4.8\,\text{fm}\,\]You need to login to perform this action.
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