A) 60 s
B) 80 s
C) 20 s
D) 40 s
Correct Answer: D
Solution :
For 40 g amount \[40\,g\xrightarrow[half-life]{20\,s}20\,g\xrightarrow[{}]{20\,s}10g\] For 160 g amount \[160\,g\xrightarrow{10\,s}80\,g\xrightarrow[{}]{10\,s}40g\] \[\xrightarrow[{}]{10\,s}20\,g\xrightarrow[{}]{10\,s}10g\] So, after \[40s\,{{A}_{1}}\] and \[\,{{A}_{2}}\]remains same.You need to login to perform this action.
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