A) 10 cm, 10 cm
B) 15 cm, 5 cm
C) 18 cm, 2 cm
D) 11 cm, 9cm
Correct Answer: C
Solution :
Given, \[M=\frac{{{f}_{0}}}{{{f}_{e}}}=9\] and \[{{f}_{0}}+{{f}_{e}}=20\] \[{{f}_{0}}=9{{f}_{e}}\] So, \[9{{f}_{e}}+{{f}_{e}}=20\] \[{{f}_{e}}=2\,cm\] \[\therefore \] \[{{f}_{0}}=9\times 2\] \[{{f}_{0}}=18\,cm\]You need to login to perform this action.
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