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NEET AIPMT SOLVED PAPER SCREENING 2012

  • question_answer
    A spherical planet has a mass \[{{M}_{p}}\] and diameter \[{{D}_{p}}\]. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to

    A) \[4G{{M}_{p}}/D_{p}^{2}\]        

    B)        \[G{{M}_{p}}m/D_{p}^{2}\]       

    C)        \[G{{M}_{p}}m/D_{p}^{2}\]       

    D)        \[4G{{M}_{p}}m/D_{p}^{2}\]

    Correct Answer: A

    Solution :

    Force, \[F=\frac{G{{M}_{e}}m}{{{R}^{2}}}\]Here,   \[F=\frac{G{{M}_{p}}m}{{{({{D}_{p}}/2)}^{2}}}\] \[F=\frac{4G{{M}_{p}}m}{D_{p}^{2}}\] \[F=ma\] Acceleration due to gravity                 \[a=\frac{F}{m}=\frac{4G{{M}_{p}}}{D_{p}^{2}}\]


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