NEET AIPMT SOLVED PAPER SCREENING 2012

  • question_answer
    The electric field associated with an electromagnetic wave in vacuum is given by \[E=i\,40\,\cos \,(kz-6\times {{10}^{8}}t),\] where E, z and t are in volt/m, metre and. second respectively. The value of wave vector k is

    A) \[\text{2}\,{{\text{m}}^{\text{-1}}}\]  

    B)                                        \[\text{0}\text{.5}\,{{\text{m}}^{\text{-1}}}\]   

    C)        \[6\,{{\text{m}}^{\text{-1}}}\]                  

    D)        \[3\,{{\text{m}}^{\text{-1}}}\]

    Correct Answer: A

    Solution :

    Electromagnetic wave equation \[E={{E}_{0}}\cos (kz-\omega t)\]                                             ?(i) Speed of electromagnetic wave \[v=\frac{\omega }{k}\] Given, equation\[E=i\,40\cos (kz-6\times {{10}^{8}}t)\]?(ii) Comparing Eqs. (i) and (ii), we get \[\omega =6\times {{10}^{8}}\]and\[{{E}_{0}}=40i\]Here, wave factor \[k=\frac{\omega }{v}=\frac{6\times {{10}^{8}}}{3\times {{10}^{8}}}=2{{m}^{-1}}\]


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