A) \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{5}{8}\]
B) \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{3}\]
C) \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{3}{8}\]
D) \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{2}\]
Correct Answer: D
Solution :
We knows\[R\propto l\] Here, \[{{R}_{1}}+{{R}_{2}}=12\,\Omega \] and \[\frac{{{R}_{1}}\times {{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}=\frac{8}{3}\Omega \] \[\Rightarrow \] \[{{R}_{1}}{{R}_{2}}=32\,\Omega \] We get, \[{{R}_{1}}=8\] and \[{{R}_{2}}=4\] Again, \[{{R}_{1}}=\frac{12{{l}_{1}}}{{{l}_{1}}+{{l}_{2}}}\]and\[{{R}_{2}}=\frac{12{{l}_{2}}}{{{l}_{1}}+{{l}_{2}}}\] Hence, \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
