A) 256 times
B) 512 times
C) 64 times
D) 128 times
Correct Answer: B
Solution :
For \[{{10}^{\text{o}}}\] rise in temperature, n = 1 so rate \[={{2}^{n}}={{2}^{1}}=2\] When temperature is increased from \[{{10}^{\text{o}}}C\] to \[{{100}^{\text{o}}}C\], change in temperature \[=100\,-10={{90}^{\text{o}}}C,\] i.e., n = 9 So, rate \[={{2}^{9}}=512\] times Alternate method. With every 10° rise in temperature, rate becomes double, so \[\frac{r'}{r}={{2}^{\left( \frac{100-10}{10} \right)}}={{2}^{9}}=512\,\text{times}\text{.}\]
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