A) 0.1V
B) 1.0V
C) 1 mV
D) 10 mV
Correct Answer: D
Solution :
Current amplification factor\[\beta =\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}}\] Collector resistance\[\Delta {{I}_{C}}=\frac{2\,V}{2\times {{10}^{3}}\Omega }=1\times {{10}^{-3}}A\] Base current\[\Delta {{I}_{B}}=\frac{\,{{V}_{B}}}{{{R}_{B}}}=\frac{{{V}_{B}}}{1\times {{10}^{3}}}={{V}_{B}}\times {{10}^{-3}}\] Given, \[\beta =100\] Now, \[100=\frac{{{10}^{-3}}}{{{V}_{B}}\times {{10}^{-3}}}\] \[{{V}_{B}}=\frac{1}{100}V=10\,mV\]
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