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NEET AIPMT SOLVED PAPER SCREENING 2012

  • question_answer
    A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is

    A) \[2\,pV\]                            

    B) \[4\,pV\]            

    C)        \[\frac{1}{2}pV\]             

    D)        \[pV\]

    Correct Answer: A

    Solution :

    For given cyclic process, \[\Delta U=0\] \[\therefore \]\[Q=W\]Also, W = - area enclosed by the curve                   \[=AB\times AD\]                                 \[=(2p-p)(3V-V)\]                                 \[=-p\times 2V\] \[\therefore \]Heat rejected  = 2 pV


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