A) 1000
B) 500
C) 250
D) 50
Correct Answer: B
Solution :
: \[{{v}^{2}}={{u}^{2}}+2as\] \[{{(3\times {{10}^{3}})}^{2}}={{(1\times {{10}^{3}})}^{2}}+2\times a\times 1\] or \[2a=(9\times {{10}^{6}})-(1\times {{10}^{6}})=8\times {{10}^{6}}\] or \[a=4\times {{10}^{6}}m/{{s}^{2}}\] Again, \[t=\frac{2\times {{10}^{3}}}{4\times {{10}^{6}}}\sec \] or\[t=500\times {{10}^{-6}}\sec \] or \[t=500\text{ }microsec\].You need to login to perform this action.
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