A) 8/3
B) 4/3
C) 9/4
D) 3/2
Correct Answer: A
Solution :
: Initially, weight of floating body = weight of water displaced \[=volume\text{ }of\text{ }water\times density\times g\] \[=\frac{2V}{3}\times 1\times g=\frac{2Vg}{3}\] In second case, weight of floating body = weight of liquid displaced = volume of liquid\[\times \]density of liquid\[\times g\] \[=\frac{V}{4}dg\] \[\therefore \]\[\frac{Vdg}{4}=\frac{2Vg}{3}\] or \[d=\frac{8}{3}gm/cc\]You need to login to perform this action.
You will be redirected in
3 sec