A) \[2.0\times {{10}^{-5}}M\]
B) \[1.0\times {{10}^{-4}}M\]
C) \[5.0\times {{10}^{-9}}M\]
D) \[2.2\times {{10}^{-4}}M\]
Correct Answer: C
Solution :
: In 0.04 M\[CaC{{l}_{2}},[C{{l}^{-}}]=\]0.08 M \[[A{{g}^{+}}](0.08)=4\times {{10}^{-10}},[A{{g}^{+}}]=5\times {{10}^{-9}}M\]
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