A) \[\frac{Ug}{{{v}^{2}}}\]
B) \[\frac{{{v}^{2}}}{2g}\]
C) \[\frac{U}{g}\]
D) \[\frac{2U}{{{v}^{2}}}\]
Correct Answer: D
Solution :
: Kinetic energy gained = Potential energy lost \[\therefore \]\[\frac{1}{2}m{{v}^{2}}=U\] or \[m=\frac{2U}{{{v}^{2}}}\].You need to login to perform this action.
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