A) \[2.303R\times 300\,log({{V}_{2}}/{{V}_{1}})\]
B) \[2.303R\times 300\,log({{V}_{1}}/{{V}_{2}})\]
C) \[1\text{ }atm\times ({{V}_{2}}/{{V}_{1}})\text{ }litre\]
D) zero
Correct Answer: A
Solution :
: \[W=nRT\,in\,\frac{{{V}_{2}}}{{{V}_{1}}}\] \[{{V}_{1}}=\]initial volume, \[{{V}_{2}}=\]final volume T = temperature, R = gas constant.You need to login to perform this action.
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