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AMU Medical AMU Solved Paper-1996

  • question_answer
    A particle of mass m is bound by a linear potential\[U=kr\](\[k=a\]constant) and moves in a circular orbit of radius r. Its energy is

    A)  \[kr\]                

    B)  \[3/2kr\]

    C)  \[2kr\]               

    D)  \[4kr\]

    Correct Answer: A

    Solution :

    : Energy of particle\[=kr\]


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