A) \[\frac{\mu L}{1-\mu }\]
B) \[\frac{\mu L}{1+\mu }\]
C) \[\frac{L}{\mu }\]
D) \[\frac{L}{1+\mu }\]
Correct Answer: B
Solution :
: Let\[m=\]mass of unit length. The hanging part\[(l)\]pulls the chain\[(L-l)\]to right by a force \[=(wl)g\] Force of friction\[=\mu \times R=\mu m(L-l)g\] Equate the two force for equilibrium \[\therefore \] \[m\lg =\mu m(L-l)g\] Or \[l=\mu (L-l)\] or \[l=\mu L-\mu l\] Or \[l=\frac{\mu L}{(1+\mu )}\]You need to login to perform this action.
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