A) \[1:2\]
B) \[4:1\]
C) \[3:1\]
D) \[2:1\]
Correct Answer: D
Solution :
: For fundamental frequency of closed pipe: \[{{n}_{c}}=\frac{v}{4{{l}_{c}}}\] For fundamental frequency of open pipe \[{{n}_{o}}=\frac{v}{2{{l}_{o}}}\] Since\[{{n}_{o}}={{n}_{c}}\] \[\therefore \] \[\frac{v}{2{{l}_{o}}}=\frac{v}{4{{l}_{c}}}\] or \[\frac{{{l}_{o}}}{{{l}_{c}}}=\frac{2}{1}\]You need to login to perform this action.
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