A) 8
B) 7
C) 6
D) 5
Correct Answer: B
Solution :
: Isomers of\[{{C}_{5}}{{H}_{10}}\]is 7: \[\underset{1-pentene}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-CH=C{{H}_{2}}}}\,\] \[\underset{2-methylbutene}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{3}}}}\,\]\[\underset{3-methyl-1-butene}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-HC=C{{H}_{2}}}}\,\] \[\underset{2-methyl-2-butene}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,-CH=C{{H}_{3}}}}\,,\] \[\underset{\begin{smallmatrix} \,\,\,\,\,\,2-pentene \\ (c\text{ }is\text{ }and\text{ }trans) \end{smallmatrix}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-CH=HC-C{{H}_{3}}}}\,\]You need to login to perform this action.
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