A) 3.1
B) 4.1
C) 4.9
D) 6.2,
Correct Answer: D
Solution :
: Vertical height = 4.9 m \[\therefore \] \[h=ut+\frac{1}{2}g{{t}^{2}}\] or \[4.9=0+\frac{1}{2}\times 9.8{{t}^{2}}\]or\[4.9{{t}^{2}}=4.9\] or \[{{t}^{2}}=1\] or \[t=1\text{ }sec\] Horizontal velocity \[=v\] \[\therefore \] Range= 6.2 m; \[\therefore \] \[v\times time=6.2\] or \[v\times 1=6.2\] or \[v=6.2\text{ }m/s\]You need to login to perform this action.
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