A) \[{{2}^{\gamma -1}}\]
B) \[{{2}^{1-\gamma }}\]
C) \[2\gamma \]
D) \[{{2}^{\gamma }}\]
Correct Answer: D
Solution :
: For adiabatic change,\[P{{V}^{\gamma }}=\]constant. \[\therefore \] \[{{P}_{1}}{{V}^{\gamma }}={{P}_{A}}{{(2V)}^{\gamma }}\] or \[{{P}_{1}}{{V}^{\gamma }}={{P}_{A}}{{2}^{\gamma }}{{V}^{\gamma }}\] or \[{{P}_{1}}={{P}_{A}}{{2}^{\gamma }}\] or \[\frac{{{P}_{1}}}{{{P}_{A}}}={{2}^{\gamma }}\]You need to login to perform this action.
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