A) formation of amalgam
B) oxidation of tin
C) oxidation of mercury
D) reduction of mercury
Correct Answer: D
Solution :
: \[H{{g}_{2}}C{{l}_{2}}+SnC{{l}_{2}}\to \underset{black}{\mathop{2Hg}}\,+SnC{{l}_{4}}.\]You need to login to perform this action.
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